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Prove 2^n cannot be a perfect number
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2015-06-23, 02:02
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Batalov
"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
59·157 Posts
Ok, let's give it a try:
2^n is an even number.
Sum of its divisors (1 and many even numbers) is an odd number.
Hence, 2^n cannot be equal sum of its divisors.
Last fiddled with by Batalov on 2015-06-23 at
03:28
Reason: its != it's
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