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Old 2018-01-27, 22:04   #12
CRGreathouse
 
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Aug 2006

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Quote:
Originally Posted by science_man_88 View Post
That the residues mod some mersenne in the LL test, are quadratic residues mod the next mersenne.
Reason I think this to be true:

Sqr(A*p+b)= A^2(p^2)+ b^2(1^2)-b mod 2p+1 and two parts of that simplify to quadratic residues. Failure would only happen if the sums/ differences of quadratic residues wasn't a quadratic residue ( guess I may be wrong).
1 is a quadratic residue but 2 is a quadratic nonresidue mod 3.
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