For k's make a full covering set with partial algebraic factors, we only take the n for algebraic factors (i.e. not take the n for covering set for fixed prime factors)
e.g. for R24 k=4, we need an even n such that 2*24^(n/2)1 and 2*24^(n/2)+1 are both primes. (since for odd n, 4*24^n1 is always divisible by 5, and for even n, 4*24^n1 = (2*24^(n/2)1) * (2*24^(n/2)+1), thus we need n such that both these two formulas take prime values)
e.g. for R24 k=6, we need an odd n such that 2^(3q1)*3^q  1 and m*2^(3q1)*3^q + 1 are both primes (where q = (n+1)/2).
e.g. for R19 k=4, we need an even n such that 2*19^(n/2)1 and (2*19^(n/2)+1)/3 are both primes.
