Quote:
Originally Posted by davieddy
The expected primes per day for the whole project is 1/1500.
So the probability of one or more primes per day is 1  e^{=1/1500} = 1/1500.5

@Phil: THX for allowing me to participate in the sort of mathsy fun which I enjoy.
Perhaps the 0.5 is worth looking into:
1  e
^{1/X} ~ 1/X  0.5*(1/X)
^{2}
= (1/X)*(1  0.5*(1/X))
~ 1/(X*(1 + 0.5*(1/X))
= 1/(X + 0.5)
Wish I had done it that way first time.
Damn those calculators
D