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Old 2019-07-01, 20:00   #1
wildrabbitt
 
Jul 2014

3×149 Posts
Default dividing an algebraic integer by another

Hi,


I've worked out that the algebraic integer \(6+23\sqrt{2}\) is divisible by
\(2+\sqrt{2}\). I find finding these factors by looking at norms quite tiring.


Is another way to work out

\(\frac{6+23\sqrt{2}}{2+\sqrt{2}}\)


in it's simplest form?


A division algorithm for example. Please show me how it goes.

Last fiddled with by wildrabbitt on 2019-07-01 at 20:04
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