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Old 2019-04-07, 18:43   #38
Till
 
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"Tilman Neumann"
Jan 2016
Germany

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Quote:
Originally Posted by nesio View Post
S - the number of all divisors of m (excluding 1 and m).

Ok, now we understand that one.


Quote:
Originally Posted by nesio View Post
A rough model of m:
Find the maximum of (S/(m^1/3)) when m < n^1/3,
where S - the number of all divisors of m (excluding 1 and m).
Here are S and m^1/3 have equal weights in maximize function.

I'ld say this is not a model of m, but a procedure to choose the best m. A model would give a kind of score to any m. (at least)



Quote:
Originally Posted by nesio View Post
What will be?

A simple weighting function giving a "plus" for smooth m, a "minus" for big m.


This is no rocket science. We tested dozens of ways to arrange k's according to such principles, and many other constellations...
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