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Old 2009-12-19, 21:54   #5
jasonp
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Oct 2004

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Do you mean 2.2*log(p)?

Msieve picks the same multipliers your code does, and I thought it uses the Knuth-Schroeppel algorithm. A factor of p contributes 2*log(p)/(p-1) if it is not part of the multiplier, and 1*log(p)/(p-1) if it is.
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