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Old 2020-02-12, 15:03   #1
enzocreti
 
Mar 2018

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Default N congruent to 2^2^n mod(2^2^n+1)

92020 is congruent to 2^(2^2) mod (2^(2^2)+1) where 2^(2^2)+1 is a Fermat prime




Are there infinitely many numbers N congruent to (2^(2^n)) mod (2^(2n)+1) where (2^(2n)+1) is a Fermat prime?
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