Quote:
Originally Posted by Vijay
Quite nicely worked out, but there does exist a smaller 'friendly' solution. Can anybody find the small solution?

There should be several smaller solutions. My example was intended to be small but informative. Tiny solutions make poor examples because everything tends to fold in on itself. I would expect the smallest solution to come from setting h=0. That leads to the choices
x=2 (it must be a factor of 2
^{h}h+1=2)
k=1 (k and q must be factors of 2
^{x}1=3)
y=1
z=2
q=3
m=2
r=1
p=1
For the tiny solution p=1, q=3, r=1, and the equation become 4=4.
Now for a reverse challenge  how many solutions can you find between this tiny solution and my example?