Pg primes congruent to 1111 mod 42^2
pg numbers are so defined:
pg(k)=(2^k1)*10^d+2^(k1)1 where d is the number of decimal digits of 2^(k1)1.
pg(8), pg(176006) and pg(541456) are probable primes. They are cogruent to 19 mod (42) and to 1111 mod(42^2).
Do you believe these primes are infinitely many?
primes pg congruent to 19 mod 42 and to 1111 (mod 42^2)?
