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THILLIAR · 2004-12-18, 06:00

(n>5)=(2^n-1)-1

7=(2^6)-1=63

8=(2^7)-1=127

I am most likely wrong, but learning is failing, correct?

2004-12-18, 06:00	#2
THILLIAR Mar 2004 ARIZONA, USA 27₈ Posts	a novice's guess (n>5)=(2^n-1)-1 7=(2^6)-1=63 8=(2^7)-1=127 I am most likely wrong, but learning is failing, correct? Last fiddled with by THILLIAR on 2004-12-18 at 06:04