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science_man_88 · 2014-12-05, 14:05

Quote:

Originally Posted by ProximaCentauri

In mathematics, Euler's identity (also known as Euler's equation) is the equality

e^ i*pi + 1 = 0

Let´s transform this a little bit:

add 1 on both sides and square the whole thing.

That results in e^-2*pi=1, (shit Latex!)

which is apparently false !

$<br /> e^{i\pi} +1 =0$
$e^{i\pi}+2=1$
$e^{2{i\pi}} + 4(e^{i\pi}) +4 = 1$

I must be missing something.