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3 mod 4 with free parameter
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2022-09-24, 10:59
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paulunderwood
Sep 2002
Database er0rr
2·3·5
^{2}
·29 Posts
Quote:
Originally Posted by
paulunderwood
I'll call it day after verification to 10^15 of the test:
n==3 mod 4
2^n==2 mod n
(I+2^r)^n==-I+2^r mod n where I is the sqrt(-1)
gcd(r,n-1)==1
FWIW testing has reached 10^15
paulunderwood
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