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Old 2019-09-29, 12:34   #12
wildrabbitt
 
Jul 2014

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Quote:
For roots of positive real numbers a, and real values of k, everything is fine -- you've got a real-valued logarithm, defined by an integral.
Can you explain how in



\( 64^3 = e^{3log(64)} \)


the real-valued logarithm is defined by an integral and what the integral is?


or rather


\( 64^{1/2} = e^{(1/2)log(64)} \) ? ( as you said roots).

Last fiddled with by wildrabbitt on 2019-09-29 at 12:39
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