View Single Post
Old 2018-01-02, 07:20   #1
George M
 
Dec 2017

5010 Posts
Default Another "how to prove"

Quote:
Originally Posted by George M View Post
p_{n + 1} \ = \ \{\sum_{k = 1}^{n}(p_{k + 1} \ - \ p_{k}) \ : \ p_m \ = \ m^{th} \ prime \ number\}
The equation is incorrect, but seemingly correct if you add 2 to the RHS. Can anybody demonstrate a proof?
George M is offline   Reply With Quote