Thread: Another "how to prove" View Single Post
2018-01-02, 07:20   #1
George M

Dec 2017

5010 Posts
Another "how to prove"

Quote:
 Originally Posted by George M $p_{n + 1} \ = \ \{\sum_{k = 1}^{n}(p_{k + 1} \ - \ p_{k}) \ : \ p_m \ = \ m^{th} \ prime \ number\}$
The equation is incorrect, but seemingly correct if you add 2 to the RHS. Can anybody demonstrate a proof?