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Old 2004-04-24, 06:21   #3
jinydu
 
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Dec 2003
Hopefully Near M48

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Ok, it seems that ln i = (pi*i)/2, so continuing on:

phi = 2 cos ([pi*i]/2 - log 5)

phi = 2 * ([cos(pi*i)/2]*[cos(log 5)] + [sin(pi*i)/2]*[sin(log 5)])

Its getting too complicated for this text box...
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