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The Golden Section.
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2004-04-24, 06:21
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jinydu
Dec 2003
Hopefully Near M48
2×3×293 Posts
Ok, it seems that ln i = (pi*i)/2, so continuing on:
phi = 2 cos ([pi*i]/2 - log 5)
phi = 2 * ([cos(pi*i)/2]*[cos(log 5)] + [sin(pi*i)/2]*[sin(log 5)])
Its getting too complicated for this text box...
jinydu
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