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Old 2015-06-23, 02:02   #2
Batalov
 
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Mar 2008
Phi(4,2^7658614+1)/2

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Ok, let's give it a try:

2^n is an even number.
Sum of its divisors (1 and many even numbers) is an odd number.
Hence, 2^n cannot be equal sum of its divisors. \qed

Last fiddled with by Batalov on 2015-06-23 at 03:28 Reason: its != it's
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