20181231, 00:02  #12  
"Rashid Naimi"
Oct 2015
Remote to Here/There
2^{3}·269 Posts 
Quote:
https://en.wikipedia.org/wiki/Empty_product 

20181231, 00:10  #13  
Sep 2017
2×59 Posts 
Quote:
Yes but we are talking about at least one term here. Last fiddled with by SmartMersenne on 20181231 at 00:11 

20181231, 00:38  #14  
"Rashid Naimi"
Oct 2015
Remote to Here/There
2^{3}×269 Posts 
Quote:
Please see post number 6 above. Regardless of if we accept the convention to be valid or not, the ambiguity of the challenge at not clarifying the concept of productofdistinctprime makes the challenge problematic. We are left to guessing what the "PuzzleMaster" considers a valid convention. 

20181231, 01:54  #15 
Feb 2017
Nowhere
2^{2}×3^{2}×139 Posts 
Between the example and the requirement that a play actually does something, there seems to be no difficulty understanding which divisors are allowed. It could have been stated more precisely, but the cavils of the willfully obtuse are probably not a major concern of the folks writing these problems.
There does however appear to be a grammatical oopsadaisy. I believe the last comma in the statement of the problem is misplaced. It should be moved one word to the right, from after "numbers" to after "each." 
20181231, 02:08  #16  
"Rashid Naimi"
Oct 2015
Remote to Here/There
2^{3}×269 Posts 
Quote:


20181231, 02:21  #17  
Sep 2017
2·59 Posts 
Quote:
In the case of allowing a product with no terms: that would get the game into an infinite loop. And if people can't see it, their program will get into an infinite loop, so I would like to see how they will solve it. Last fiddled with by SmartMersenne on 20181231 at 02:40 

20181231, 15:29  #18 
Feb 2017
Nowhere
2^{2}·3^{2}·139 Posts 
The set B in the example (but not the set A) can easily be expanded to four positive integers. Not that this is of any use in solving the problem, of course...

20181231, 22:08  #19 
Sep 2017
2·59 Posts 

20190101, 03:33  #20  
"Forget I exist"
Jul 2009
Dumbassville
2^{6}·131 Posts 
Quote:
Quote:
Last fiddled with by science_man_88 on 20190101 at 03:35 

20190101, 15:03  #21 
Feb 2017
Nowhere
2^{2}×3^{2}×139 Posts 

20190101, 17:59  #22 
"Rashid Naimi"
Oct 2015
Remote to Here/There
4150_{8} Posts 
It is quite an interesting challenge.
I have tens of glasses which are 15/16 full but I am quite peptomestic about filling the last 1/16 of any of them. One interesting aspect is that the square root of the sums seem to form in interesting and different patterns. Many are symmetrical around a 45° diagonal. Others form a row of primes then primesx2 then semiprimes then semiprimesx2 and other patterns as well. And of course my posts would not be complete without a few painfully annoying nags to some: The challenge does not define any rules regarding repeating terms within/between the two sets A & B. Without such clarifications many trivial solutions can be found. Last fiddled with by a1call on 20190101 at 18:01 
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