Thread: M51 arithmetic
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Old 2019-01-07, 16:59   #15
science_man_88's Avatar
"Forget I exist"
Jul 2009

26·131 Posts

I've decided I'll divulge my methods (even though I'm not meant for this forum), which mostly rely on a multiplicative partition, of an easy to get to, relatively nearby or exact value:

48=8*6*1= 8*(2+5+8-9)*(9/(3*3))
49=7*7 = (8+2+5-8)*((9/9)+3+3)
50=10*5+0= ((8+2)*5)+(8-9+(9/(3/3)))
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