Quote:
Originally Posted by enzocreti
what instead about the equation:
a(2*a^2+2*b^2+c^2+d^2)=(2*a^3+2*b^3+c^3+d^3)?
Again a=1,b=1,c=1,d=1 is a solution
a=5, b=4, c=6, d=1 is another solution
are there solutions with d>1?

if a is even c and d need be same parity.
if a=b then ac^2+ad^2=c^3+d^3
etc.