View Single Post
 2020-10-22, 11:37 #6 Dr Sardonicus     Feb 2017 Nowhere 22·13·83 Posts Yes, substituting x for 7! does make things much easier to handle. The obvious regrouping of the first part of the expression gives $2x^{\frac{1}{4}}\cdot$$x^{\frac{1}{2}}\;+\;x^{\frac{-1}{2}}$$^{\frac{1}{2}}$ The "obvious" multiplication then gives $2\sqrt{x+1}$. I note that things can go wrong for complex values of "x" that aren't positive real numbers.