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2020-02-23, 20:17   #2
R.D. Silverman

Nov 2003

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Quote:
 Originally Posted by wildrabbitt Hi, the following is something I've been reading. He started from the power series $$\sum_{n=1}^\infty \big(\frac{n}{q}\big)x^n=\frac{1}{1-x^q}\sum_{m=1}^{q-1}\big(\frac{m}{q}\big)x^m=\frac{xf(x)}{1-x^q}$$ say, and by putting this in the formula $$\Gamma(s)n^{-1}=\int_0^1 x^{n-1}(\log x^{-1})^{s-1} \mathrm{d}x$$ he obtained $$\Gamma(s)L(s)=-\int_0^1\frac{f(x)}{x^q-1}(\log x^{-1})^{s-1}\mathrm{d}x$$ I'm stuck because I can't see how he put what he put in the formula. Can anyone explain it step by step?
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