and I suppose it also truncates the "bit"-length ? The factor I am talking about is indicated as
103 9075527700594867141608327604401
taking the log clearly indicates that 103 is the correct bitlength of this number,
so how can it be truncated (which I understand as being chopped at a certain point in the sequence) ?
The above number has the factorisation
23*239*6709*55313*163861*27150982078609
where the first five factors are all smaller than 2^18