and I suppose it also truncates the "bit"-length ? The factor I am talking about is indicated as

103 9075527700594867141608327604401

taking the log clearly indicates that 103 is the correct bitlength of this number,

so how can it be truncated (which I understand as being chopped at a certain point in the sequence) ?

The above number has the factorisation

23*239*6709*55313*163861*27150982078609

where the first five factors are all smaller than 2^18