Thread
:
Multiplication method for factoring natural numbers
View Single Post
2019-04-06, 23:42
#
30
nesio
Apr 2019
2
^{5}
Posts
Hi, Thilo!
You can check this rough (very rough) model of m on your source data of n:
maximum(S/(m^1/3)) and m < n^1/3,
where S - the sum of all divisors of m.
Here are S and m^1/3 have equal weights in maximum function.
What will be?
nesio
View Public Profile
Find More Posts by nesio