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Old 2019-04-06, 23:42   #30
nesio
 
Apr 2019

25 Posts
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Hi, Thilo!
You can check this rough (very rough) model of m on your source data of n:
maximum(S/(m^1/3)) and m < n^1/3,
where S - the sum of all divisors of m.
Here are S and m^1/3 have equal weights in maximum function.
What will be?
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