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Unusual differentiation
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2004-08-16, 03:08
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jinydu
Dec 2003
Hopefully Near M48
2×3×293 Posts
I do know how to differentiate f(x) = x^x. Maybe that can help:
f(x) = x^x = (e^ln x)^x = e^(x*ln x)
f '(x) = x*ln x * e^(x*ln x) = x*ln x * x^x = (x^x) * x * ln x
Last fiddled with by jinydu on 2004-08-16 at
03:09
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