Quote:
Originally Posted by mfgoode
How would you differentiate
y = x^( x ) ^(x^)xright up to infinity ?
In other words y =X to the power of x to the power of xup to infinity ?
Mally

For 0<x<1, this can't converge to 1. notice that y=x^y. So if, say for x=1/2, we would have that 1=y=(1/2)^1=1/2.
I'm not much into complex analysis, so I don't know all the places that this function converges. However, here is a hint on taking the derivative:
Let f[x] := x^f[x], where x^f[x] is defined as x^f[x] := exp[f[x]*Log[x]], i.e. the number e=2.71828... to the power of f[x]*Log[x], where Log[x] is the natural log. Take the derivative, and solve for df/dx
This has a fairly nice answer, and is related to the Lambert Wfunction. (I really don't know anything about it, though
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