Quote:
Originally Posted by Jacob Visser
y=(x+3+sqrt((x3)24(x23x)))/2
and
y=(x+3+sqrt((x3)24(x23x)))/2
the determinant must be positive, thus (x3)^{2}4(x^{2}3x)=3x^{2}+2x+3 >= 0

Miscutting and pasting and completely wrong calculation on my part :(
(I had the values already and just needed to justify them ;)
It should be
y=(x+3+sqrt((x3)24(x23x)))/2
and
y=(x+3sqrt((x3)24(x23x)))/2
(x3)
^{2}4(x
^{2}3x)=)=3x
^{2}+6x+9
and this is non negative for x larger or equal to 1 and less or equal to +3.
As for:
Quote:
Originally Posted by Wacky
But don't leave out the x=y part. As noted, the relationship holds for any integer k and x = y = k.

It was covered in my first sentence :
Quote:
Originally Posted by Jacob Visser
the easy part is x=y and needs no explaining
