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Old 2008-01-14, 22:42   #10
gd_barnes
 
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May 2007
Kansas; USA

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Quote:
Originally Posted by Jean Penné View Post
In the definitions of these four conjectures, the k multipliers must be odd!
For example : 46902*2^n+1 is the same as 23451*2^(n+1)=+1 and if n is odd, n+1 is even, so, you are testing an even exponents candidate!
So, the 8 even k's remaining are relevant to the even n conjecture, and not to the odd n one...

Also, I tested k = 46623 up to n = 79553 and found a prime, so me are almost matching now... I am terminating to gather my results, and will send them to this thread as soon as possible.
Regards,
Jean
Well, DUH!! I will remove the even k's that obviously go with the even-n conjecture from my LLRing.


Gary
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