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R.D. Silverman · 2014-07-15, 16:26

Quote:

Originally Posted by science_man_88

just asking things:

I'm guessing it's known that $(2^{p-1}\eq 1 \text { mod p^2}) == (2^{2n-1}-1\eq 2n^2+2n \text { mod 4n^2+4n+1})$ where 2n+1 =p; if so has anything useful come out of it ?

Would a moderator please move this (and succeeding) gibberish to the crank
math sub-forum?