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Forum: Abstract Algebra & Algebraic Number Theory 2018-12-28, 00:19
Replies: 2
Views: 5,077
Posted By science_man_88
(2kp+1)(2jp+1)=4jkp^2+2(k+j)p+1 = 2(2jkp+k+j)p+1 ...

(2kp+1)(2jp+1)=4jkp^2+2(k+j)p+1 = 2(2jkp+k+j)p+1 so as many as the natural numbers up to X/(2p) of form 2jkp+k+j for some natural numbers k and j.
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