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 Showing results 1 to 25 of 58 Search took 0.02 seconds. Search: Posts Made By: cyrix
 2014-01-25, 12:19 Replies: 494 Sticky: Reservations Views: 40,000 Posted By cyrix Reserving FermatFactor=37,110e15,130e15 ... Reserving FermatFactor=37,110e15,130e15 Cyrix
 2013-12-05, 11:13 Replies: 494 Sticky: Reservations Views: 40,000 Posted By cyrix FermatFactor=37,100e15,110e15 Cyrix FermatFactor=37,100e15,110e15 Cyrix
 2013-12-05, 11:11 Replies: 622 Sticky: Results Views: 54,661 Posted By cyrix no factor for k*2^36+1 in k range: 250P to 260P... no factor for k*2^36+1 in k range: 250P to 260P (94-bit factors) [mmff 0.27 mfaktc_barrett96_F32_63gs] Cyrix
 2013-10-04, 11:50 Replies: 494 Sticky: Reservations Views: 40,000 Posted By cyrix reserving FermatFactor=36,250e15,260e15 ... reserving FermatFactor=36,250e15,260e15 Cyrix
 2013-10-04, 11:47 Replies: 622 Sticky: Results Views: 54,661 Posted By cyrix no factor for k*2^36+1 in k range: 220P to 230P... no factor for k*2^36+1 in k range: 220P to 230P (94-bit factors) [mmff 0.27 mfaktc_barrett96_F32_63gs]]
 2013-09-03, 12:54 Replies: 494 Sticky: Reservations Views: 40,000 Posted By cyrix Reserving FermatFactor=36,220e15,230e15 ... Reserving FermatFactor=36,220e15,230e15 Cyrix
 Forum: Information & Answers 2011-08-10, 04:22 Replies: 103 Views: 8,101 Posted By cyrix first guess Hi! My English isn't very well, so let us concentrate on the math. The main problem is determining the probability, that P-1 finds a factor under the condition, that trial factoring didn't. So...
 Forum: Lounge 2006-12-03, 01:32 Replies: 118 Views: 8,039 Posted By cyrix Mine, too :) Thanks. :) Mine, too :) Thanks. :)
 Forum: Lounge 2006-10-09, 21:08 Replies: 118 Views: 8,039 Posted By cyrix All done. All done.
 2006-09-11, 21:53 Replies: 171 Views: 15,349 Posted By cyrix 2^32582657 -3 is divisible by 23 and 523657 (and... 2^32582657 -3 is divisible by 23 and 523657 (and no other prime < 5000000) Cyrix
 Forum: News 2006-09-04, 19:13 Replies: 201 Views: 25,068 Posted By cyrix M44 might be, no, *IS* here George Woltman on the prime-list: > A computer has reported finding the 44th known Mersenne prime! I'll > arrange for a verification run soon. More details will be available > when the...
 Forum: Miscellaneous Math 2006-07-30, 12:11 Replies: 20 Views: 1,447 Posted By cyrix Hi bearnol! Your "proof" provides nothing,... Hi bearnol! Your "proof" provides nothing, and is also false. First: What do you show? If your "proof" would be correct, it would only show, that the zeors of the zeta function are lying...
 Forum: Lounge 2006-03-06, 20:33 Replies: 85 Views: 6,818 Posted By cyrix Mine arrived, too. Thanks to Xyzzy and Curtis... Mine arrived, too. Thanks to Xyzzy and Curtis Cooper! :) Cyrix
 Forum: Lounge 2006-02-18, 12:14 Replies: 85 Views: 6,818 Posted By cyrix Mailed 2/24. Mailed 2/24.
 Forum: News 2005-12-24, 15:30 Replies: 265 Views: 24,177 Posted By cyrix :banana: :banana: :banana: :banana: :banana: :banana:
 Forum: Lounge 2005-09-11, 20:02 Replies: 21 Views: 1,231 Posted By cyrix Hi ixfd64! If \pi is random (which is... Hi ixfd64! If \pi is random (which is unproven, but most people think so), then you can find every finite string (of numbers) in the decimal expansion of \pi . cyrix
 Forum: Math 2005-09-11, 19:50 Replies: 12 Views: 1,152 Posted By cyrix These two statements are related, yes. But the... These two statements are related, yes. But the 5^... is stronger, because it uses the litte Fermat, too. For q=53 the number 5 is a quadratic residue, but M_q does not hold a fermat-test with base...
 Forum: Math 2005-09-11, 18:51 Replies: 12 Views: 1,152 Posted By cyrix We proved the "\Rightarrow", the "\Leftarrow" is... We proved the "\Rightarrow", the "\Leftarrow" is true for all prime q=4n+1<3000 (I tested it with Maple). But even when this is a real test (and the equvialence is true), it would cost as much...
 Forum: Math 2005-09-11, 17:30 Replies: 12 Views: 1,152 Posted By cyrix In the End: Your (second) Conjecture is false, sorry Hi Tony! For q=53 we have M_q=6,361 \cdot 69,431 \cdot 20,394,401 , for all of these primefactors 5 is a quadratic residue, so 5 is also a quadratic residue of M_q=M_{53} , so this is a counter...
 Forum: Math 2005-09-11, 15:00 Replies: 12 Views: 1,152 Posted By cyrix sorry Tony! I messed something up. Now in a... sorry Tony! I messed something up. Now in a better form: M_q \equiv 3 \pmod 4 , but since 5 \equiv 1 \pmod 4 the reciprocity law works in the same way, So you can find a solution X with ...
 Forum: Math 2005-09-11, 10:47 Replies: 12 Views: 1,152 Posted By cyrix Hi T.Rex! For prime M_q with q \equiv 1... Hi T.Rex! For prime M_q with q \equiv 1 \pmod 4 (and q>1) your conjecture is true: Because of the quadratic reciprocity law (Gauß) 5 is a quadratic residue of M_q , iff M_q is quadratic...
 Forum: Math 2005-09-10, 22:54 Replies: 12 Views: 1,152 Posted By cyrix Hi T.Rex! Your Conjecture is false! All... Hi T.Rex! Your Conjecture is false! All conditions are equal: R^2+R-1=0 mod M, this means R_{1/2}= -1/2 +- \sqrt{1/4+1}= (-1+-sqrt(5))/2. For q=5 we have M=31 and sqrt(5)= +-6, thus we have...
 Forum: Riesel Prime Search 2004-12-27, 22:22 Replies: 599 Views: 32,878 Posted By cyrix Hi, I'd like to work on k=105 a little bit... Hi, I'd like to work on k=105 a little bit further. Cyrix
 Forum: Factoring 2004-10-23, 17:14 Replies: 261 Views: 18,417 Posted By cyrix Hi, "M1061 completed 100 ECM curves, B1=44000000,... Hi, "M1061 completed 100 ECM curves, B1=44000000, B2=4290000000" Cyrix
 Forum: Prime Sierpinski Project 2004-06-24, 23:06 Replies: 15 Views: 2,446 Posted By cyrix It's just me: cyrix p.s.: At the moment my... It's just me: cyrix p.s.: At the moment my computer is working for the rieselsieve-project, so in the next time I won't be so active in this project. Cyrix
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