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Search: Posts Made By: xilman
Forum: Homework Help 2019-09-28, 17:40
Replies: 13
Views: 6,395
Posted By xilman
Hmm? (2i)^4 = ((2i)^2)^2 = (-4)^2 = 16. ...

Hmm?

(2i)^4 = ((2i)^2)^2 = (-4)^2 = 16.
(-2i)^4 = ((-2i)^2)^2 = (-4)^2 = 16.

ITYM, 16^(1/4) = ±2, ±2i.

More generally, there are n distinct n-th roots of unity.

Ah, the OP is interested...
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