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 Showing results 1 to 2 of 2 Search took 0.00 seconds. Search: Posts Made By: Dr Sardonicus
 Forum: Wagstaff PRP Search 2018-05-13, 12:38 Replies: 7 Views: 6,291 Posted By Dr Sardonicus Of course, norm(v) = -2, not 2. Luckily, all I... Of course, norm(v) = -2, not 2. Luckily, all I needed this for in the case p == 5 (mod 6) was to check that v was relatively prime to M, i.e. vR + MR = R. I'm not sure whether this was just a...
 Forum: Wagstaff PRP Search 2018-05-10, 14:31 Replies: 7 Views: 6,291 Posted By Dr Sardonicus let p > 3 be a prime number, M = (2^p + 1)/3. ... let p > 3 be a prime number, M = (2^p + 1)/3. Then M == 3 (mod 8). Let u = Mod(x, x^2 - 4*x + 1), so that u^2 - 4*u + 1 = 0. Let R = Z[u] = ring of algebraic integers in Q(sqrt(3)). If p ==...
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