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 mfgoode 2007-04-21 17:09

Simple Arithmetic!

:smile:

Is this equation correct ?

2.*sq.rt (2/3) = sq.rt. [2*(2/3)] ? Yes or No ?

Mally :coffee:

 mfgoode 2007-04-22 04:31

Wrong local time!

Moderator the time marked for my post is 3hrs before I got on my computer and posted this message an hour or so later!

Something wrong with the software? The next post on has been put later than my post and hence given preference.

Mally :coffee:

P.S. it has been immediately corrected during writing of this reply.

 m_f_h 2007-04-22 04:53

[quote=mfgoode;104213]:smile:
Is this equation correct ?
2.*sq.rt (2/3) = sq.rt. [2*(2/3)] ? Yes or No ?
Mally :coffee:[/quote]
It depends on what the "." and "*" mean (in regular expressions (regexp) the former represent an arbitrary character, in DOS command lines the latter represent an arbitrary sequence of characters ;
finally [ ] might be the "Gaussklammer"...

 retina 2007-04-22 08:11

One side is sqrt(2) larger than the other. Is that supposed to be a puzzle or just something you don't understand?

 victor 2007-04-22 11:06

[QUOTE=mfgoode;104213]:smile:

Is this equation correct ?

2.*sq.rt (2/3) = sq.rt. [2*(2/3)] ? Yes or No ?

Mally :coffee:[/QUOTE]

Yes it is.
If . and * mean multiplication, and sq, rt are variable.
2 x y (2/3) = x y 2 (2/3) ...

 S485122 2007-04-22 11:26

If . and * are multiplication what is the meaning of the concatenation of the two in the first part of the first term : "2.*sq".

In the formula I see a lot of (intentional ?) inconsistencies : "2." versus "2*", "rt" versus "rt."

My first intention was asking what the ".", the "*" and "sq.rt" meant. But then I realised it could be the core of the riddle.

 Orgasmic Troll 2007-04-22 16:53

1 Attachment(s)

Moderator the time marked for my post is 3hrs before I got on my computer and posted this message an hour or so later!

Something wrong with the software? The next post on has been put later than my post and hence given preference.

Mally :coffee:

P.S. it has been immediately corrected during writing of this reply.[/QUOTE]

.

 mfgoode 2007-04-23 03:41

characters!

[QUOTE=m_f_h;104244]It depends on what the "." and "*" mean (in regular expressions (regexp) the former represent an arbitrary character, in DOS command lines the latter represent an arbitrary sequence of characters ;
finally [ ] might be the "Gaussklammer"...[/QUOTE]

Sorry for the confusion.

2.*sq.rt (2/3) = sq.rt. [2*(2/3)] ? Yes or No ?

means 2 multiplied by the square root of 2/3 = square root of 2 multiplied by 2/3. So in one side the 2 is outside the square root on the other 2 is inside the square root.

* is multiplication, []are brackets, Its not the Gaussklammer.
'.' is full stop.
It is not a riddle! Its just a maths curiosity which looks odd and that it is wrong but it is right.

Mally :coffee:

 mfgoode 2007-04-23 03:46

[QUOTE=Orgasmic Troll;104299].[/QUOTE]

I had my launchcast radio on, on 'My Station' and believe it or not that guy on the keyboard was actually keeping in time to it. Amazing!

Mally :coffee:

 Orgasmic Troll 2007-04-23 05:26

so you're claiming that $$(2)( \sqrt{\frac{2}{3}}) = \sqrt{(2) (\frac{2}{3})}$$?

$$(2)( \sqrt{\frac{2}{3}}) = \sqrt{(4) (\frac{2}{3})} \neq \sqrt{(2) (\frac{2}{3})}$$

 mfgoode 2007-04-23 08:38

:smile:

Yes.

The version you have given is totally wrong

Mally :coffee:

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