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-   -   N congruent to 2^2^n mod(2^2^n+1) (https://www.mersenneforum.org/showthread.php?t=25221)

enzocreti 2020-02-12 15:03

N congruent to 2^2^n mod(2^2^n+1)
 
92020 is congruent to 2^(2^2) mod (2^(2^2)+1) where 2^(2^2)+1 is a Fermat prime




Are there infinitely many numbers N congruent to (2^(2^n)) mod (2^(2n)+1) where (2^(2n)+1) is a Fermat prime?

retina 2020-02-12 15:13

[QUOTE=enzocreti;537422]92020 is congruent to 2^(2^2) mod (2^(2^2)+1) where 2^(2^2)+1 is a Fermat prime

Are there infinitely many numbers N congruent to (2^(2^n)) mod (2^(2n)+1) where (2^(2n)+1) is a Fermat prime?[/QUOTE]Of course there are.

16 mod 17 = 16
33 mod 17 = 16
50 mod 17 = 16
...

So what.

enzocreti 2020-02-12 15:14

ok
 
ok nevermind


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