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davar55 2007-03-19 22:22

Easy Arithmetic
 
Find three consecutive odd cubes whose sum is a four (decimal) digit
number with identical digits.

davieddy 2007-03-20 09:46

I found four candidates, (the four digit numbers being
1197,2403,4257,6903).
What am I missing?

Mini-Geek 2007-03-20 13:14

[quote=davieddy;101480]I found four candidates, (the four digit numbers being
1197,2403,4257,6903).
What am I missing?[/quote]
I found the same candidates. Are we doing something wrong or did davar55 word the problem wrong?

Zeta-Flux 2007-03-20 14:29

Maybe by "consecutive" he meant distinct.

S485122 2007-03-20 14:37

I did find the same candidates, but changing the problem to 3 consecutive squares I get 5555 = 41^2+43^2+45^2

davieddy 2007-03-20 16:21

That's quite a coincidence.
Must be what he meant. Well spotted!

davar55 2007-03-20 17:47

Mea culpa. I did mean three consecutive odd squares.
There's something to be said for repeating a preview before posting.
And on such a simply stated problem.
:blush:


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