Help with Math Problem
I'm preparing for a Math Exam next Monday and this is a problem on a Past Paper. Could someone help me out (but don't provide the answer, just a hint please)?
A coin is biased so that when it is tossed the probability of obtaining heads is 2/3. The coin is tossed 1800 times. Let X be the number of heads obtained. Find: a) The mean value of X b) The standard deviation of X Of course, a) is easy to find. The mean of X = (2/3)*1800 = 1200. 
There is a simple and well known formula for the variance of binomial distribution  you should probably look it up and memorize it for the exam. If you must derive it, then find the variance of the outcome for flipping the coin [B]one[/B] time, then note that 1800 flips is the sum of 1800 iid random variable, so their variances add.

Hope this helps.
[url]http://psych.rice.edu/online_stat/chapter5/binomial.html[/url] [url]http://cnx.rice.edu/content/m11024/latest/[/url] 
X is a random variable with binomial distribution
The probabilty of getting [b]n[/b] heads out of [b]N[/b] trials with a coin that has probabilty [b]p[/b] of coming up heads (and probabilty q=1p of getting tails) is (N,n)*p[sup]n[/sup]q[sup]Nn[/sup] = N!/n!(Nn)! * p[sup]n[/sup](1p)[sup]Nn[/sup] where (N,n) is a binomial coefficient the standard deviation is Sqrt[N*p*(1p)] Sorry if I gave too much away 
A little too much. Oh well, I have the answer now. The standard deviation is 20. Thanks

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