N congruent to 2^2^n mod(2^2^n+1)
92020 is congruent to 2^(2^2) mod (2^(2^2)+1) where 2^(2^2)+1 is a Fermat prime
Are there infinitely many numbers N congruent to (2^(2^n)) mod (2^(2n)+1) where (2^(2n)+1) is a Fermat prime? 
[QUOTE=enzocreti;537422]92020 is congruent to 2^(2^2) mod (2^(2^2)+1) where 2^(2^2)+1 is a Fermat prime
Are there infinitely many numbers N congruent to (2^(2^n)) mod (2^(2n)+1) where (2^(2n)+1) is a Fermat prime?[/QUOTE]Of course there are. 16 mod 17 = 16 33 mod 17 = 16 50 mod 17 = 16 ... So what. 
ok
ok nevermind

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