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-   -   Aliquot sequences that start on the integer powers n^i (https://www.mersenneforum.org/showthread.php?t=23612)

 garambois 2018-11-10 18:25

OK, all is done.
Thank you very much for your help !

As for me, I have completed the calculations for n=2^476, finished with a p77.
And now, all (10^10+19)^i are up to 120 digits for i from 1 to 15.

 RichD 2018-11-12 00:37

Added a few hundred terms to 7^108 with nothing interesting to report.

 gd_barnes 2018-11-17 07:26

I tested all of n=5 up to size 102 and cofactor of 96 (fully ECM'd). Here are the updates:

5^112 +137 iterations
5^114 +88
5^118 +28
5^122 +30
5^126 +18
5^128 +32
5^130 +35
5^132 +20
5^138 +34
5^140 +1449 (A wild ride!)
5^142 +32

No reservations.

I am also working on all of n=6. No reservations. I'll be done in ~2 days.

 RichD 2018-11-17 17:49

 gd_barnes 2018-11-19 11:16

I tested all of n=6 up to size 102 and cofactor 97 (fully ECM'd). Here are the updates:

6^47: 1638 U104 (100) +47 iterations
6^51: 220 U108 (97) +4
6^53: 765 U103 (99) +80
6^57: 889 U102 (100) +35
6^59: 242 U107 (101) +16
6^61: 700 U102 (99) +183
6^63: 421 U111 (108) +39
6^65: 417 U103 (99) +48
6^69: 1291 U110 (103) +141
6^71: 224 U102 (100) +96
6^73: 1053 U106 (102) +777 (!)
6^75: 267 U106 (100) +56
6^83: 1029 U102 (97) +8
6^85: 544 U108 (98) +67
6^91: 167 U111 (97) +27
6^93: 1072 U102 (98) +11
6^95: 2370 U102 (99) +2319 (Dropped to 9 digits!!)
6^97: 550 U109 (103) +7
6^99: 178 U102 (100) +116
6^101: 1746 U104 (103) +19
6^103: 519 U106 (103) +104
6^105: 394 U102 (100) +9
6^107: 93 U104 (97) +28
6^109: 93 U104 (100) +46
6^111: 124 U104 (98) +53
6^113: 174 U102 (101) +142
6^115: 97 U108 (100) +56
6^117: 966 U111 (99) +7
6^119: 136 U102 (98) +100
6^121: 149 U107 (99) +119
6^127: 22 U106 (100) +6

I also extended a couple of n=5 from my previous posting from cofactor 96 to 97 (fully ECM'd):
5^118: 269 U104 (98) +42 iterations
5^156: 8 U110 (109) +1

All base 5 and 6 are now size>=102 and cofactor >=97.

I am now working on all of n=7 testing to the same limit. I'll be done in ~2-3 days.

No reservations.

 kar_bon 2018-11-19 15:43

1300 lines done on 11^46, now at 121 digits.

 garambois 2018-11-19 18:15

OK the web page is updated.

Thank you very much to all for your help !

:smile:

On my side, I finished the aliquot sequences 2^477 (one more green cell !).
And 3^136, 3^137, 3^140, 3^142, 3^157 and 3^160 are now size >= 10^120.
So, that makes 6 more orange cells in the table of base 3 !

And I think someone calculated terms from sequence 2^490.
It cannot be moved from index 3 to index 7 on its own !
The prime numbers that factor these terms are too large.

:brian-e:

 science_man_88 2018-11-19 18:41

[QUOTE=garambois;500510]OK the web page is updated.

Thank you very much to all for your help !

:smile:

On my side, I finished the aliquot sequences 2^477 (one more green cell !).
And 3^136, 3^137, 3^140, 3^142, 3^157 and 3^160 are now size >= 10^120.
So, that makes 6 more orange cells in the table of base 3 !

And I think someone calculated terms from sequence 2^490.
It cannot be moved from index 3 to index 7 on its own !
The prime numbers that factor these terms are too large.

:brian-e:[/QUOTE]

what other use of powers() in PARI/GP are there ?

 gd_barnes 2018-11-19 23:45

7^96 term 1267 merges with sequence 4788 term 6 with a value of 60564.

Sequence 4788 is being worked on by the main project.

7^96 is now at term 13777, size 203, cofactor size 174 !!

I'm guessing that this is now the longest n^i sequence.

:smile:

 gd_barnes 2018-11-20 07:01

[QUOTE=sweety439;497952]Why stop at 11? I suggest stop at 24

Now, I am running 12 and 13

(also, I have run 2^n-1 and 2^n+1 for n<=64)[/QUOTE]

[QUOTE=sweety439;497955]Why you ran large prime (10^10+19)?

Now I am running 439[/QUOTE]

[QUOTE=MisterBitcoin;498044]
Note: There was no need to add n=12; 13 and 439. These are normal sweety thinks.
[/QUOTE]
Sweety is not a serious searcher. He just reserves stuff, searches for a little while to a very low search-depth, and then waits for others to extend his searches. You can release all of his reservations for n=12, 13, and 439.

 richs 2018-11-20 14:53

I have been running 439^32 and 439^34 on a non-reservation basis.

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